Asians are labelled as maths genius.. Lets see who can find the mistake behind this 4=3 Proof: a=b 4a-3a=4b-3b 4(a-b)=3(a-b) 4=3(a-b)/(a-b) 4=3
well i'm not agenius in math but for me the answer will be : (a²-b²) (4-3)= 0 and then u get 2 solutions a²-b²=0 or 4-3=0 ( and 4=3)
That's my answer. The a=b in the first line assumes that a and b ARE equal. Sub in the number 2 for both a and b, then try to see what's wrong with the math problem again (a²-b²) (4-3)= 0 -huh Dunno how you got that.
oops the ² was wrong, i was thinking about another thing but here the right answer 4a-3a=4b-3b 4a-3a-4b+3b=0 4(a-b) + 3 (a-b) =0 (a-b) (4+3)= 0 then 2 solutions: a-b=0 or 4+3=0 a=b 4=-3
Actually... 4a-3a-4b+3b = 0 would become 4(a-b)+3(-a+b) = 0 4(a-b)+3(-a+b) is not the same as 4(a-b) + 3 (a-b)
^ ugh...makes my head hurts ><;; so much for asians being good in math..or maybe it's just mee -sweat
maybe for u it's not but for me it is and this is like that i learn math before get my bachelor...no matter where is the sign it will be the same thing ..;the place of sign will have a meaning only if the unknow is determine by advance (sorry for my bad english)
This "equation" proved NOTHING. If you use the simplest operation possible, then: a=b 4a-3a=4b-3b if you do the simple arithematic, not grouping them... a=b Plus, because given a=b a-b=0 (a-b)/(a-b)=0/0 it's indefinite, not cancels out. Oops, someone said that already. the two are equal since a=b is the given premise. a=b a-b=0 -a+b=b-a=0
Hmmmm Ive been looking at all these answers for a while now, like 20 mins LOL and i think Secluded's was the best. Hmm and after thinking a bit more, U are saying 4=3 only if a=b, which i dunt feel has proved anything...but then again thats just me^^ very interesting tho
lol this further proves why he's gettin his ass kicked all the time... -lol he needs to take those math skills n design booby traps...
A variable represents a value, even if it's not determined in advance, you always have to be careful with it's sign. For example. If you had 2 variables, c and d which are not equal. c - d would not be the same as d - c just because they haven't been declared yet. So if we were to suddenly sub in 1 for "c" and 2 for "d", c - d = -1 -c + d = 3 Notice how secluded ended up with "4=3(a-b)/(a-b)" and you got "(a-b)(4+3)=0"? It's because of your misplaced negative sign. From 4(a-b)+3(-a+b) = 0, you'll lead to secluded's, hiake, and my answer as it would turn into 4(a-b) = 3(a-b) From 4(a-b) + 3 (a-b) = 0, you'll get the answer you got (a-b)(4+3) = 0 -a+b = b-a is always the same. (That's wasn't what I was commenting on tho ) -a+b and a-b however are not. If a and b are equal, than yes, they may result in the same thing, but it's still a math mistake to not place negatives in the right place (as shown by the above example).
yeh but the fact is if one variable is named a and another b, they cannot be equal otherwise it would be a=a or b=b So no matter what equations you try to do, you cant because its based on a=b which is wrong
Cokacola, u said "who can find the mistake within this" yeh? Meaning u got the question from somewhere, so wheres the correct answer??
Do not worry about your difficulties in Mathematics. I can assure you mine are still greater. Albert Einstein
