The ultimate challenge!!!

Discussion in 'Random / Offtopic' started by chi_man, Sep 12, 2007.

  1. BabyRain

    BabyRain Doppelgänger of da E.Twin

    Aww ... don't be naughty my dear.
     
  2. chi_man

    chi_man Well-Known Member

    fearless'one is correct

    ye srry, I already edited like an hour ago :p

    your post wasn't there?!?!?! It just suddenly pops up lol... but doesnt taxloss died 120 years after xiaojia was born is the same as Xiaojia was born when Taxloss already died for 120 years??

    hmm seems like it does make a difference lol, its correct
     
  3. hiake

    hiake Vardøgr of da E.Twin

    But assignments are so evil that we have to banish them in the dungeons -tongue2
     
  4. chi_man

    chi_man Well-Known Member

    lol anyways... according to the rules: First person to post the correct answer got the points :D so hiake got it since she was a lil faster than babyrain :D

    gonna add new ones now
     
  5. hiake

    hiake Vardøgr of da E.Twin

    It does make a difference:

    "taxloss died 120 years after xiaojia was born" implies that Xiaojia was born before Taxloss (assumming Taxloss led a normal lifespan)

    "Xiaojia was born when Taxloss already died for 120" implies that Xiaojia was born AFTER Taxloss died.
     
  6. BabyRain

    BabyRain Doppelgänger of da E.Twin

    Chiman, i didn't answer cuz i was pointin out ur mistake and confirming it first... but hiake... LOL.
    It's all good coz she's my darling -hug
     
  7. chi_man

    chi_man Well-Known Member

    ah ic lol :p need to work on my stating thingy's lloo, and again hiake was a lil fasater than baby_rain lol
     
  8. chi_man

    chi_man Well-Known Member

    lol you're editing your posts so damn fast, anyways, better luck next time if you wanna compete with the smartass hiake :p
     
  9. BabyRain

    BabyRain Doppelgänger of da E.Twin

    ^Uh like i said i didn't put the answer coz technically ur question was wrong lol. So hiake's answer shdn't count until u confirmed the question ahaha. It's ok i am just kidding :p
     
  10. BabyRain

    BabyRain Doppelgänger of da E.Twin

    3 1 2 2 1 1
    the numeral 1 is just one one
    one one can be written as 1 1
    1 1 is actually two ones.
    two ones can be written as 2 1
    2 1 is one two and one one
    one one and one two is 1 2 1 1
    1 2 1 1 is one one, one two, and two ones.
    one one, one two, and two ones is 1 1 1 2 2 1.
    1 1 1 2 2 1 is three ones, two twos, and one one.


    Me!

    If Hiake is telling the truth, then I must be lying. If I am lying, then XJ is telling the truth. If XJ is telling the truth, then both me and hiake are lying. That contradicts Hiake is telling the truth.

    If XJ is telling the truth, then both Hiake and me are lying. If Hiake is lying, I must be telling the truth, which implies that the XJ is lying, which contadicts our hypothesis that XJ is telling the truth.

    If I am telling the truth, then XJ must be lying. The key is that XJ said BOTH hiake AND me are telling lies. If either one of us are telling the truth, this statement is proven false. So if XJ is lying, then EITHER hiake or me or both are telling the truth. We can assume hiake is lying based on the hypothesis that I was telling the truth. None of this is self-contradictory, so it's the only possible answer.

    (shit this is so long it shd be 5 points lol)
    Taxloss just needs to run faster than flaming.. let the lion catch flaming and devour him ahahaha.

    White bear picked the first paper, laughed and tore it off or destroyed it somehow... so they had to look at the other paper ... which marks "DIE" ...-lol Of course Knoc couldn't admit he was cheating.

    P/s: Name is BabyRain, not baby_rain... tq :p
     
  11. hiake

    hiake Vardøgr of da E.Twin

    X = 504, that's the smallest (non-zero) X possible.
     
    #91 hiake, Oct 12, 2007
    Last edited: Oct 12, 2007
  12. zero_c

    zero_c Well-Known Member

    1,190
    86
    0


    X = 0
     
  13. hiake

    hiake Vardøgr of da E.Twin

    D*mn, I forgot about zero -lol
     
  14. BabyRain

    BabyRain Doppelgänger of da E.Twin

    Red? Since they can see the flags on others' heads, Hiake must haf seen the rest with blue.
    And there's at least 1 red flag. (Altho she sure took a pretty long time... -lol)
     
  15. chi_man

    chi_man Well-Known Member

    correct!

    correct, it was so easy that it wouldn't be worth 5 points :p

    both correct BabyRain :p

    correct

    lol, I also haven't thought about the X being zero lol :p but correct too!
     
  16. chi_man

    chi_man Well-Known Member

    wrong! if hiake saw the other one with blue, then she would immediately say RED instead of waiting 39 minutes :p

    damn you guys are solving it so fast,, I dont even have time to come up with new ones lol, ur catching up fast BabyRain -lol
     
  17. BabyRain

    BabyRain Doppelgänger of da E.Twin

    Hiake said she's havin a RED flag coz.......

    If she was havin a blue flag then one of the others would have reasoned "she's got blue so if I had blue then the other last one would know for sure that she's red and would have jumped up."

    Therefore she knows she's havin a red after 39 minutes!
    (ur answer gave me the clue lmao)

    P/s: Pls edit my name at the score too -lol
     
  18. bbes

    bbes Incredible

    can everybody see each others flags then?
     
  19. BabyRain

    BabyRain Doppelgänger of da E.Twin

    He weighs meat of course. :p

    "We all know that BabyRain is a very chaotic person and messes up the boxes." <_<

    XJ needs to spend 1 euro as long as she knows the weight of a Comedy dvd.
    Assume the weight of Comedy dvd = Y
    Weight of action Dvd = Y + 2

    Method:
    Label the boxes 1 through 10. Put one DVD from box number one on the scale. Then, on top of that, put two DVDs from box number two. Then put three from box number three on those, four from box four, and so on.

    There are now 55 DVDs on the scale. Weigh them. If they were all Y grams, the total weight would be 55 x Y grams. However, we know that one or more of the DVDs weighs Y + 2.

    Subtract (55 x Y) grams from the total weight, and this gives you the "extra weight" for the heavier DVDs. Since you know that they are each two grams heavier than the others, you can divide this excess weight by two, and the result tells you how many of the heavier DVd's are on the scale, and this number tells you which box contains the action dvds.
     
  20. chi_man

    chi_man Well-Known Member

    correct, I was helpful huh? :p your name will be edited lol

    yep